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Locus of path of particle is y 2x. Whatwill be direction of particle, when passesthrough (2, 2) is(a) tan (2) with +ve x - axis.(b) tan (0.5) with +ve x -axis.(c) tan (4) with +ve x-axis(d) . |
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Answer» direction can be found out just by differentiation of the locus y² = 2x=> 2ydy/dx = 2 or dy/dx = 1/y so, at point (2,2) , the value of tan∅ is 1/(2) or ∅ = tan.inv(0.5) option B. |
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