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`log_(10)tna 1^(@) + log_(10) tan 2^(@) + ...+ log _(10) tan 89^(@)` बराबर है |
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Answer» Correct Answer - A `log tan 89^(@) = log cot 1^(@) = - log tan 1^(@)` ` :. log tan 1^(@) + log tan 2^(@)` ` + ...+ log tan 44^(@) + log tan 45^(@)` ` - log tan 44^(@) - ...- log tan 2^(@)` ` - log tan 1^(@) = log tan 45^(@) = log 1 = 0` |
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