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    				| 1. | `log_100 a-log_a 0.0001 , a >1`A. 2B. 3C. 4D. none of these | 
| Answer» Correct Answer - C We have, `2log_(100)a-log_(a)0.0001` `=2log_(100)a-log_(a)(100)^(-2)` `=2log_(100)a+2log_(a)100` `=2(log_(100)a+log_(a)100)` `=(log_(100)a+(1)/(log_(100)a))` `ge2xx2=4" "[becausex+(1)/(x)ge2" for all "xgt0]` | |