InterviewSolution
Saved Bookmarks
| 1. |
`Log_9tan(pi/6)` |
|
Answer» `log_9(tan(pi/6)) = log_9(1/sqrt3)` `= 1/2log_3(3^(-1/2))` `= -1/2**1/2log_3 3` `= -1/4**1` `= -1/4` `:. log_9(tan(pi/6)) = -1/4` |
|