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m +m2(0.015+1.2)of mass 60 kg jumps with a horizontal velocity of 6 m s1 onto a stationary cartEXAMPLE 2.28: Awith frictionAssume noless wheels. The mass of the cart is 6 kg. What is her velocity as the cart starts movinexternal unbalanced force is acting in horizontal direction.)CCE 2013]SOLUTION: Here, mass of the girl, m1 = 60 kg: initial horizontal velocity of the girl, ul-6 m s-1; mass of the6 kg and initial velocity of the cart, u: O

Answer»

Similar problem. Just replace 40 by 60and 5 by 6

no external force => momentum is constant.

momentum of girl = 40 * 5 = 200 kg-m/sec momentum of girl and cart = total momentum of the girl + momentum of cart = 200 + 0 = 200 kg m/sec speed = 200 / (40 + 3) = 4.65 m/sec4.1

thanks



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