Mass number of a radioactive element is 232 and its atomic number is 90. When this element undergoes certain nuclear reactions, it transforms into an isotopeof lead with a mass number 208 and an atomic number 82. Determine the number of alpha and beta dacay that can occur.

Mass number of a radioactive element is 232 and its atomic number is 9

1.	Mass number of a radioactive element is 232 and its atomic number is 90. When this element undergoes certain nuclear reactions, it transforms into an isotopeof lead with a mass number 208 and an atomic number 82. Determine the number of alpha and beta dacay that can occur.
Answer» Solution :`""_(90)X^(232) OVERSET(4beta)to ""_(94)Y^(232)+ 4""_(4)E^(0)(4beta "decay")` From the result of `beta` decay, `""_(94)X^(232) overset(6 alpha)to ""_(82)Y^(208)+ 6""_(2)He^(4)(6 alpha "decay")` The number of `alpha` decay = 6 The number of `beta` decay = 4