1.

Mass of the following "element" // "compound" is given in grams. Calculate it.s moles and number of "molecules"//"atoms" : 22 g carbon dioxide (CO_(2))

Answer»

Solution :Number of moles of 22 G `CO_(2) = ("mass of "CO_(2))/("molecular mass of "CO_(2))`
`= (22)/(44)`
= 0.5 MOLE
Number of MOLECULES in 22 g `CO_(2) = "Number of moles of "CO_(2) XX "Avogadro number"`
`= 0.5" mole" xx 6.023 xx 10^(23) "molecules"// "mole"`
`= 3.0115 xx 10^(23)` molecules


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