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Match the following for the equation `x^(2)+a|x|+1=0` where, a is a parameter. |
Answer» Correct Answer - `a to s; b to r; c to q; d to p ` `atos,btor,ctoq,d""to""p` Obviously when `age0`, we have no roots a all the terms are followed by+ve sign. Also for a=-2, we have `x^(2)-2|x|+1=0` or `|x|-1=0impliesx=pm1` Hence, the equation has two roots. Also when `alt-2`, for given equation `|x|=(-apmsqrt(a^(2)-4))/(2)gt0` Hence, the equation has four roots as `|-a|gtsqrt(a^(2)-4)`. Obviously, the equation has no three roots for any value of a. |
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