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Maximum value of (9sinθ + 13 cosθ) is –1). √1902). √1603). √2704). √250 |
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Answer» According to formula, MAXIMUM value of (a sin x ± b cos x) = √(a2 + b2) Minimum value of (a sin x ± b cos x) = - √(a2 + b2) ∴ Maximum value of (9sinθ + 13 cosθ) is = √(92 + 132) = √(81 + 169) = √250 |
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