1.

Maximum value of (9sinθ + 13 cosθ) is –1). √1902). √1603). √2704). √250

Answer»

According to formula,

MAXIMUM value of (a sin x ± b cos x) = √(a2 + b2)

Minimum value of (a sin x ± b cos x) = - √(a2 + b2)

∴ Maximum value of (9sinθ + 13 cosθ) is

= √(92 + 132) = √(81 + 169) = √250


Discussion

No Comment Found