InterviewSolution
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InterviewSolution
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Mechanism of a hypothetical reaction `X_(2) + Y_(2) rarr 2XY` is given below: (i) `X_(2) rarr X + X` (fast) (ii) `X+Y_(2) hArr XY+Y` (slow) (iii) `X + Y rarr XY` (fast) The overall order of the reaction will be :A. 1B. 2C. 0D. `1.5` |
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Answer» Correct Answer - D we know that , slowest step is the rate determining step . `therefore "rater "( I) = K_(1)[X][Y_(2)]` Now, from equation (i) i.e., `X_(2) to 2x["fast"]` `K_(eq)=([X]^(2))/([X_(2)])` `[X]= {K_(eq)|X_(2)|}^(1//2).. . (ii) ` Now , substitutethe value of [x] from equation (ii) in equation (i) , we get Rate (I) `=K_(1)(K_(eq))^(1//2)[X_(2)]^(1//2)[Y_(2)]=K[X_(2)]^(1//2)[Y_(2)]` `therefore ` order of reaction `=(1)/(2) +1=(3)/(2)=1.5` |
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