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mgFind reading of spring balanceNote: Spring balance reads thrust of body which is read in kg-wt.1kg5kgsics

Answer»

The reaction in the spring balance will be the sum of the tension in the string having 1kg (t1) amd 5kg (t2) each.

now for tension. 10-t1 = -1a.....(1)and , 50-t2 = 5a.....(2)

and also a = (50-10)/6 = 40/6 =(20/3)m/s² putting a in 1 and 2t1 = 10+20/3 = 50/3N and t2 = 50-100/3 = 50/3 N

so, the spring shows t1+t2 = 2*(50/3) = 100/3 N.



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