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min6.Five point charges, each of value +q areplaced on five vertices of a regularhexagon of side LM. What is themagnitude of the force on a point chargeof value - coloumb placed at the centreof the hexagon?Lans. F=f = ameo and47E LL

Answer»

Five point charges each of charge q are placed on five vertices of a regular hexagon of side l .Find the magnitude of resultant force on charge -q placed at center of hexagon

Out of 5 vertices

4 vertices forces will cancel each other

as distance from center = same but direction is opposite

so only force will be from the vertices , opposite to which no charge

F = k q(q)/l²

Force will be attractive in nature as opposite charges



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