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Answer» Given : ➳ MASS of CAR = 1000kg ➳ Mass of truck = 8000kg ✪ Before collision : ➳ Velocity of car = 32m/s ➳ Velocity of truck = 4m/s ✪ After collision : ➳ Velocity of car = -8m/s (negative sign shows OPPOSITE direction.) To Find : ➨ Velocity of truck after collision. SoluTion : ⇒ Since, no external force acts on the whole system (car + truck), we can apply concept of momentum conservation to SOLVE this type of questions. ⇒ Momentum is defined as the product of mass and velocity. ⇒ As per law of momentum conservation, $\Rightarrow\tt\:Initial\:momentum=Final\:momentum\\ \\ \Rightarrow\tt\:m_1u_1+m_2u_1=m_1v_1+m_2v_2\\ \\ \Rightarrow\tt\:(1000)(32)+(8000)(4)=(1000)(-8)+(8000)v_2\\ \\ \Rightarrow\tt\:32000+32000=-8000+8000v_2\\ \\ \Rightarrow\tt\:64000+8000=8000v_2\\ \\ \Rightarrow\tt\:v_2=\dfrac{72000}{8000}\\ \\ \Rightarrow\underline{\boxed{\bf{v_2=9\:ms^{-1}}}}$

Answer»

Given :

➳ MASS of CAR = 1000kg

➳ Mass of truck = 8000kg

✪ Before collision :

➳ Velocity of car = 32m/s

➳ Velocity of truck = 4m/s

✪ After collision :

➳ Velocity of car = -8m/s

(negative sign shows OPPOSITE direction.)

To Find :

➨ Velocity of truck after collision.

SoluTion :

⇒ Since, no external force acts on the whole system (car + truck), we can apply concept of momentum conservation to SOLVE this type of questions.

⇒ Momentum is defined as the product of mass and velocity.

⇒ As per law of momentum conservation,

$\Rightarrow\tt\:Initial\:momentum=Final\:momentum\\ \\ \Rightarrow\tt\:m_1u_1+m_2u_1=m_1v_1+m_2v_2\\ \\ \Rightarrow\tt\:(1000)(32)+(8000)(4)=(1000)(-8)+(8000)v_2\\ \\ \Rightarrow\tt\:32000+32000=-8000+8000v_2\\ \\ \Rightarrow\tt\:64000+8000=8000v_2\\ \\ \Rightarrow\tt\:v_2=\dfrac{72000}{8000}\\ \\ \Rightarrow\underline{\boxed{\bf{v_2=9\:ms^{-1}}}}$