1.

Moment of inertia of a body about an axis is `4kg-m^2`. The body is initially at rest and a torque of `8Nm` starts acting on it along the same axis. Workdone by the torque in `20s`, in joules is

Answer» `tau=IalpharArralpha=(tau)/I=2, theta=1/2 alphat^(2)=400`,
`omega=tau theta=3200 J`


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