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mon.13. Amass of 6 kg is suspended by a rope of length 2 m fromthe ceiling. A force of 50 N in the horizontal directionis applied at the midpoint P of the rope as shown.What is the angle the rope makes with the vertical inequilibrium? (Take g = 10 m/s.) Neglect mass of therope.(N.C.E.R.T. Solved Example)MM1T cos11mT = 50 NT sin1mto y6 kg wt

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