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Most people interpret a `9.0 dB` increase in sound intensity level as a doubling in loudness. By what factor must the sound intensity be increase to double the loudness?A. `1 m//s`B. `2 m//s`C. `3 m//s`D. `4 m//s` |
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Answer» Correct Answer - B `f_(b) = f_(1) - f_(2)` or `10 = 1700 ((340)/(340 + nu_(2))) - 1700 ((340)/(340 + nu_(1)))` `= 1700(1 + (nu_(2))/(340))^(-1) - 1700 (1 + (nu_(1))/(340))^(-1)` Using Binomial therefore, we get `10 = 1700(1 - (nu_(2))/(340)) - 1700 (1 - (nu_(1))/(340))` `= (nu_(1) - nu_(2)) ((1700)/(340))` :. `nu_(1) - nu_(2) = 2 m//s` |
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