Moving coil galvanometer (MCG) has 10 turns each of length12 cm and br

1.	Moving coil galvanometer (MCG) has 10 turns each of length12 cm and breadth 8 cm. The coil of M.C. G. carries a currentof 125uA and is kept perpendicular to the uniform magneticfield of induction 10 T. The twist constant of phosphor bronzefibre is 12x10 Nm/degree. Calculate the deflectionproduced
Answer» deflection produced is 10° Explanation: given data TURN = 10 LENGTH = 12 cm breadth = 8 cm CURRENT = 125 uA uniform magnetic field of induction = $10^{-2}$ T twist constant = 12 x $10^{-9}$ Nm/degree solution Current flowing through coil of MCG current I = $(\frac{c}{nBA} )\theta$ .................................1 so here $\theta$ will be $\theta$ = $(\frac{nBA}{c} )l$ put here VALUE we get $\theta$ = $\frac{10\times 10^{-2}\times 12 \times 10^{-2}\times 8 \times 10^{-2}\times 125 \times 10^{-6}}{12\times 10^{-9}}$ $\theta$ = 10° so deflection produced is 10° Learn more : current produce a deflection 1. brainly.in/question/13004528