1.

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Answer»

Mass of the truck = 1,000 kg Initial velocity (u) = 20 m/s Final velocity (v) = 0 m/s Displacement (S) =? Force acting (F) = - 5000 N Solution: We know that F = ma -5000 = 1000*aa = - 5000/1000 = - 5 m/s^2

Now, using 2as = v^2 - u^2 2 × (-5) x s = 0^2 - 20^2-10s = - 400s = -400/-10 = 40 m

Therefore, distance travelled by truck before stopping is 40 m



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