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MUULUU ULICILLIUMIN6.m/s2At the end of a race, a runner decelerates from a velocity of 9 m/s at a rate of 2(a)zas-V-02How far does he travel in the next 5 s?What is his final velocity?How much time will it take to finally stop?(c)2x |
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Answer» Initial velocity, u = 9m/sAcceleration, a = -2m/s^2 (a)time, t = 5 secs = ut + (1/2)at^2s = 45 + (1/2)(-2)25s = 45 - 25s = 20 m (b)final velocity, v = u + atv = 9 + (-2)5v = 9 - 10 = -1 m/s (c)to stop, v = 00 = u + at0 = 9 + (-2)t2t = 9t = 4.5 sec Hope it helps.Mark as best if I am correct. |
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