1.

`N_(2(g))+2O_(2(g)) rarr 2NO_(2) +X kJ` `2NO_((g))+O_(2(g)) rarr 2NO_(2(g))+Y kJ` The enthalpy of formation of `NO` isA. `(2X-2Y)`B. `X-Y`C. `1//2(Y_X)`D. `1//2(X-Y)`

Answer» `N_(2)(g)+2O_(2)(g)rarr 2NO_(2)(g),DeltaH =+X kJ …(i)`
`2NO(g) +O_(2)(g) rarr 2NO_(2)(g),DeltaH =+YkJ …(ii)`
Substracting equation (ii) from equation (i), we get
`N_(2)(g) +O_(2)(g) rarr 2NO(g),DeltaH = X-Y`
or `Delta_(f)H^(Theta) (NO) = ((X-Y))/(2) kJ mol^(-1)`


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