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n iron rod of 4 cm2 cross-sectional area isparallel to a magnetising field of 103 A/m. If themagnetic flux passing through it is 4x104 wb,then find permeability, relative permeability andmagnetic susceptibility of the substance. |
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Answer» First magnetic induction B = flux / area is to be found out. B = 4 x 10^-4/4 x 10-4= 1 TNow permeability μ = B / HGiven H = 1000 A/m, and found B = 1TSo μ = 1/1000 = 10-³H/m relative permeability is μ/μo = 10^-3/4π*10^-7 = 796.17Now with susceptibility chi we have to follow μ/μo = 1 + chiμo = 4 pi x 10-7 => chi = 10^-3/4π*10^-7 -1 = 796.17-1 = 795.17 |
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