Ncert class 9. chapter 8 - motion. 3) A train starting from a railway

1.	Ncert class 9. chapter 8 - motion. 3) A train starting from a railway and moving with uniform acceleration attains a speed 40 km/h in 10 mins. Find its acceleration. the ans is 0.0185. ...and I used the formula [a= v-u/t] and my result is 0.185...i am not getting the zero...pls help me..if anybody can .
Answer» Given : ➳ Initial velocity = zero ➳ FINAL velocity = 40kmph ➳ Time interval = 10min To Find : ➨ Acceleration of train. Concept : ➢ Acceleration is DEFINED as the rate of change in velocity. ➢ It is a vector quantity having both magnitude as well as direction. ➢ It can be positive, negative or zero. ➢ SI unit : m/s² ✴ FIRST equation of kinematics : $\bigstar\:\underline{\boxed{\tt{v=u+at}}}$ Conversion : ➠ 1kmph = 5/18mps ➠ 40kmph = 40 × 5/18 = 11.11mps ➠ 10min = 10 × 60 = 600s Calculation : $\longrightarrow\tt\:v=u+at\\ \\ \longrightarrow\bf\:a=\dfrac{v-u}{t}\\ \\ \longrightarrow\tt\:a=\dfrac{11.11-0}{600}\\ \\ \longrightarrow\underline{\boxed{\tt{a=0.0185\:ms^{-2}}}}$

Ncert class 9. chapter 8 - motion. 3) A train starting from a railway and moving with uniform acceleration attains a speed 40 km/h in 10 mins. Find its acceleration. the ans is 0.0185. ...and I used the formula [a= v-u/t] and my result is 0.185...i am not getting the zero...pls help me..if anybody can .

Answer»

Given :

➳ Initial velocity = zero

➳ FINAL velocity = 40kmph

➳ Time interval = 10min

To Find :

➨ Acceleration of train.

Concept :

➢ Acceleration is DEFINED as the rate of change in velocity.

➢ It is a vector quantity having both magnitude as well as direction.

➢ It can be positive, negative or zero.

➢ SI unit : m/s²

✴ FIRST equation of kinematics :

$\bigstar\:\underline{\boxed{\tt{v=u+at}}}$

Conversion :

➠ 1kmph = 5/18mps

➠ 40kmph = 40 × 5/18 = 11.11mps

➠ 10min = 10 × 60 = 600s

Calculation :

$\longrightarrow\tt\:v=u+at\\ \\ \longrightarrow\bf\:a=\dfrac{v-u}{t}\\ \\ \longrightarrow\tt\:a=\dfrac{11.11-0}{600}\\ \\ \longrightarrow\underline{\boxed{\tt{a=0.0185\:ms^{-2}}}}$

Given :

To Find :

Concept :

Conversion :

Calculation :

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