NEET(UG) - 2019(ODISHA)019 (ODISHA)5.An object flying in air with velo

1.	NEET(UG) - 2019(ODISHA)019 (ODISHA)5.An object flying in air with velocity(20 +251 - 12k) suddenly breaks in two pieceswhose masses are in the ratio 1. 5. The smallermass flies off with a velocity (1001 + 351 +8h)The velocity of the larger piece will be(1) 41 +23j - 16k (2) - 100f – 351 - 8k(3) 20î +15j - 80k (4) -201 - 15) - 80k
Answer» ANSWER: Speed of the heavy mass is given as $v_2 = 4 \hat i + 23 \hat j - 16 \hat k$ Explanation: As we KNOW that during explosion there is no EXTERNAL FORCE on it So we can use momentum conservation $P_i = P_f$ so we will have $6m(20 \hat i + 25 \hat j - 12 \hat k) = m v_1 + 5m v_2$ given that the speed of smaller mass is $v_1 = 100\hat i + 35 \hat j + 8 \hat k)$ now we have $120 \hat i + 150 \hat j - 72 \hat k = (100 \hat i + 35 \hat j + 8 \hat k) + 5 v_2$ $20 \hat i + 115 \hat j - 80 \hat k = 5 v_2$ $v_2 = 4 \hat i + 23 \hat j - 16 \hat k$ #Learn Topic : Momentum conservation brainly.in/question/12203652