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    				| 1. | निम्न फलानो की सांतत्यता की जाँच कीजिये - (i) ` f (x) = {{:( (1)/(1 - e^(1//x))"," x ne 0), ( 0" ""," x = 0):} ` पर (ii) ` f ( x) = {{:( e^(1//x)","x ne 0),(0" ""," x = 0):} ` पर (iii) ` f ( x ) = {{:( (1)/(1 + e^(1//x))"," x ne0), ( 0" ""," x =0):} ` पर | 
| Answer» ( i) ` f( 0 - 0) = lim _ ( hto 0) f ( 0 - h) = lim _ ( hto 0) (1) /( 1 - e ^(-1//h))` ` = lim _ ( hto 0) ( 1)/(1 - (1 - ( 1) /(h) + ( 1 ) /(h ^(2)) * ( 1) /(2!) - ...))` ` = lim _ ( hto 0) ( 1 ) /(((1)/(h) - (1)/(h^(2)*2 !) + ...)) = (1) /((1)/(0) - ( 1)/(0*2!)) = ( 1)/(oo) = 0 ` इसी प्रकार ` f ( 0 + 0 ) = 0 ` और ` f ( 0 ) = 0 ` ` rArr f ( 0 + 0) = f ( 0 - 0 ) = f (0) ` | |