InterviewSolution
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InterviewSolution
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निम्नाकिंत के बीच का कोण ज्ञात कीजिए - |
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Answer» माना `vec a = 2 hati "तथा" vec b = 3hati - 4hatj` ` veca . vec b = (2hati).(3hati - 4 hati)` `= 6 (hati , hati ) + 0(hatj. hati)+ (hatk. hatk)` `= 6.1 + 0.1 + 0.1 =6` `|veca | = |3hati - 4 hatj + 0hatk | = sqrt((3)^(2) + (-4)^(2) + (0)^(2)]) = sqrt(4) = 2` तथा ` |vec b| = |3hati - 4hatj +0hatk | = sqrt([(3)^(2) + (-4)^(2) + 0])` ` sqrt(25) = 5` अब , ` cos theta = (vec a . vecb )/(vec|a|.vec|b|)= (6)/(2xx5) = (6)/(10) = (3)/(5)` ` rArr theta = cos^(-1) ((3)/(5))` . |
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