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InterviewSolution
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Nitrogen dioxide `(NO_(2))` dissociates into nitric oxide (NO) and oxygen `(O_(2))` as follows `NO_(2) to 2NO + O_(2)` If the rate of decrease of concentration of `NO_(2)` is `6.0 xx 1-^(12)` mol `L^(-1) s^(-1)`. What will be the rate of increase of concentration of `O_(2)`?A. `3 xx 10^(-12) mol L^(-1) s^(1)`B. `6 xx 10^(-12) mol L^(-1) s^(-1)`C. `1 xx 10^(-12 mol L^(-1) s^(1)`D. `1.5 xx 10^(-12) mol L^(-1) s^(1)` |
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Answer» Correct Answer - A For the reaction, `2NO_(2) to 2NO + O_(2)` `-(1)/(2) (d[NO_(2)])/(dt) = (1)/(2) (d[NO])/(dt) = (d[O_(2)])/(dt)` `- (d[NO_(2)])/(dt) = 6 xx 10^(-12) mol L^(-1) s^(-1)` `(d[O_(2)])/(dt) = 3 xx 10^(-12) mol L^(-1) s^(-1)` |
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