

InterviewSolution
Saved Bookmarks
1. |
nth term of an A.P. is an . If a1 + a2 + a3 = 102 and a1 = 15, then find a10 . |
Answer» Given a1 = 15 and a1 + a2 + a3 =102 a + a + d + a + 2d = 102 ⇒ 3a + 3d = 102 ⇒ 3 (a + d) = 102 ∴ (a + d) = 102/3 = 34 ⇒ d = 34 – a = 34 – 15 = 19 ∴ a = 15, 0 = 19 then its 10th term = a10 = a + (10 – 1)d = a + 9d = 15 + 9(19) = 15 + 171 = 186 ∴ 10th term of it = 186 |
|