1.

Number of natural life times `(T_(av))` required for a first order reaction to achieve `99.9%` level of comletion isA. `6.9`B. `1.5`C. `0.105`D. `9.2`

Answer» Correct Answer - A
Time required for `99.9%` reaction is `10` times of half-life period.
`T_(99.9) = 10T_(50)`
But `T_(50) = (0.693)/(k)`
`:. T_(av) = (1)/(k)`
and `T_(50) = 0.693 T_(av)`
`:. T_(99.9) = 10 xx 0.693 T_(av) = 6.93 T_(av)`


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