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NUMERICAL EXERCISEA current of 10 A passes through two very long wires held parallel to each otherseparated by a distance of 1m. What is the force per unit length between them. |
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Answer» Answer: Force on ONE wire due to other is F=BI 2
l where MAGNETIC field B= 2πr μ
I 1
due to FIRST wire at DISTANCE r. Thus force per unit length between them is F/l=BI 2
= 2πr μ 0
I 1
I 2
= 2π×1 (4π×10 −7 )×10×10
=2×10 −5 N/m |
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