1.

NUMERICAL EXERCISEA current of 10 A passes through two very long wires held parallel to each otherseparated by a distance of 1m. What is the force per unit length between them.​

Answer»

Answer:

Force on ONE wire due to other is F=BI

2

l where MAGNETIC field B=

2πr

μ

0

I

1

due to FIRST wire at DISTANCE r.

Thus force per unit length between them is F/l=BI

2

=

2πr

μ

0

I

1

I

2

=

2π×1

(4π×10

−7

)×10×10

=2×10

−5

N/m



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