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InterviewSolution
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`O_(2)` undergoes photochemical dissociation into one normal oxygen atom and one excited oxygen atom. Excited oxygen atom is `1.967 eV` more energetic than normal . The dissociation of `O_(2)` into two normal atoms of oxygen required `498 kJ mol^(-1)`, what is the maximum wavelength effective for photochemical dissociation of `O_(2)`?A. `1.01 nm`B. `1.64 nm`C. `1.74 nm`D. `2.74 nm` |
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Answer» Correct Answer - C `O_(2) rarr O +O^(**)`, Dissociation energy `=468 kJ mol^(-1)=(498xx10^(3))/(6.02xx10^(23)) J mol^(-1)=8.27xx10^(-19) J molecules^(-1)` Extra energy of the excited atom `=1.967 eV=1.967xx1.6xx10^(-19) J=3.15xx10^(-19) J atom^(-1)` `lambda=(hc)/(E)=(6.626xx10^(-24)xx3xx10^(8))/(11.42xx10^(-19))=174xx10^(-9) m` Thus, `lambda=174 nm` |
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