1.

of mass 2kg moves on a smooth horizontal plane under the action of a single force3i4+ 4 j) newton. Under this force it is displaced from (0,0) to (-1m, 1m). Find the work done by4.icleF (in Joule)

Answer»

Given force = 3i+4jand ,the displacement vector is given by p2 - p1

ds = -1i +1j

now , work done will be = F.ds = (3i+4j)•(-i+j) = -3+4 = 1J



Discussion

No Comment Found

Related InterviewSolutions