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On a day when the speed is `345 m//s`, the fundamental frequency of a closed organ pipe is `220 H_(Z)` . (a) How long is this closed pipe? (b) The second overtone of this pipe has the same wavelength as the third harmonic of an open pipe . How long is the open pipe ? |
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Answer» Correct Answer - A::B::C::D (a) `f = (nu)/(4l)` `:. l = (nu) / (4 f) = (345)/(4 xx 220)` `= 0.392 m` (b) `5((nu)/(4l_(c))) = 3((nu)/(2l_(o)))` `:. l_(o) = (6)/(5) l_(c) = (6)/(5) (0.392)` `= 0.470 m` |
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