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On increasing the plate separation of a charged condenser, the energyA. increasesB. decreasesC. remains unchangedD. becomes zero |
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Answer» Correct Answer - A Energy `U = (1)/(2)(Q^(2))/(C )` for a charged capacitor charge `Q` is constant and with the increase in separation `C` will decrease `(C prop (1)/(d))`, So overall `U` will increase. |
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