InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
On the basis of the following thermochemical data `:` `(Delta_(f)G^(@)H_((aq.))^(+)=0)` `H_(2)O_((l))rarr H_((aq.))^(+)+OH_((aq.))^(-),DeltaH=57.32kJ` `H_(2(g))+(1)/(2)O_(2(g))rarrH_(2)O_((l)),DeltaH=-286.20kJ` The value of enthalpy of formation of `OH^(-)` ion at `25^(@)C` is `:`A. `+228.88 kJ`B. `-343.52 kJ`C. `-22.88 kJ`D. `-228.88 kJ` |
|
Answer» Correct Answer - D `H_(2)O_((l))rarr H^(+)(aq)+OH^(-)(aq) , Delta H=57.32` `Delta H=[Delta H_(f)(H^(+))+Delta H_(f)(OH^(-)]-Delta H_(f)(H_(2)O)` From eq. (ii) `Delta H_(f)(H_(2)O)=-286.20 kJ` Given `Delta H_(f)(H^(+)) = 0` `therefore 57.32 =0+Delta H_(f)(OH^(-))-(-286.20)` `Delta H_(f)=-228.88 kJ` |
|