1.

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in (figure). The change in internal energy of the gas during the transition is (gamma=3//5)

Answer»

`-20 KJ`
20 J
`-12 KJ`
20 KJ

Solution :Change in internal energy
`DELTAU = nC_v DELTAT and T = (PV)/(NR)`
`DeltaT = T_2 -T_1 = (P_2V_2-P_1V_1)/(nR) , C_v =R/(gamma-1)`
`DeltaU = (nR)/(gamma-1)((P_2V_2-P_1V_1)/(nR))=(P_2V_2-P_1V_1)/(gamma-1)`
`= (5xx4-2xx6)/(3/5-1) = (20-12)/(-2//5)=(-8)/(2//5)- 20 KJ`


Discussion

No Comment Found

Related InterviewSolutions