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                                    One part of an iron - pillar is cylindrical and the rest part is conical . The radii of the cylindrical and conical part 8 cm and their heights are 240 cm and 36 cm respectively , If the weight of 1 cc iron be 7.8 gm , what will be the total weight of the pillar ? | 
                            
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Answer» The radius of the cylindrical part = 8 cm and its height = 240 cm ` :.` the volume of the cylindrical part ` = 22/7 xx 8^(2) xx 240 ` cubic cm ` = 22/ 7 xx 64 xx 240 ` cc Again , the radius of the conical part = 8 cm and its height = 36 cm ` :. ` the volume of the conical part ` = 1/3 xx 22/7 x 8^(2) xx 36 ` cc ` = 22/7 xx 64 xx 2 ` cc So, the total volume of the pillar ` = ( 22/7 xx 64 xx 240 + 22/7 xx 64 xx 12) ` cc ` = 22/7 xx 64 xx( 240 + 12 )` cc Now, the weight of 1 cc pillar is 7.8 gm ` :.` the weight of 1 cc pillar is 7.8 gm ` :. ` the weight of 1 cc pillar is 7.8 gm ` :.` the weight of 1 cc pillar is 7.8 gm ` :. ` the weight of ` 22/7 xx 64 xx 252 ` cc is `7.8 xx 22/7 xx 64 xx 252 ` gm = 395366.4 gm = 395 . 3664 kg Hence the weight of the total pillar = 395.37 kg (approx )  | 
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