InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The lower part of a tent is of shape of a right circular cylinder , the height of which is 3.5 metres . The upper part of the the tent is of a shape of a right circular cone . If the total height of the tent be 9.5 metre and it its diameter of base be 5 metre , then how much quantity of tarpailin will be required to make 14 such tents ? |
|
Answer» The diameter of the base of the tent = 5 cm ` :. ` the radius of the base of the tent = `5/2 ` m = 2.5 m height of the cylindrical part = 3.5 m ` :.` the curve surface area of this ppart = ` 2pirh = 2 xx 22/7 xx 2.5 xx 3.5 ` sq - metre = 55 sq- metre The radius of the conical upper part of the tent = 2.5 m and height = `(9.5 - 3.5) m = 6 ` m The slant height of the conical ` = sqrt(r^(2) + h^(2))` or , ` l = sqrt((2.5)^(2) + (6)^(2)) ` or , `l = sqrt(42.25 )` m = 6.5 m ` :. ` the curved surface area of this conical part ` = pirl ` ` = 22/7 xx 2.5 xx 6.5 ` sq- m ` :.` the tarpaulin required to make one tent = ` ( 55 + 22/7 xx 2.5 xx 6.5 ) `sq - metre ` :. ` the tarpaulin required to make 14 tent = ` 14 ( 55 + 22/7 xx 2.5 xx 6.5) ` sq - metre Hence the required quantity of tarpaulin = 1485 sq - metre |
|