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(P->Q)->(^Q) is ____ |
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Answer» Answer Correct OPTION is (p∧q)→r P→(∼q→r) =p→(∼q∨r) ∼p∨(∼q∨r) (∼p∨∼q)∨r ∼(p∧q)∨r (p∧q)→r |
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