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Particles of m1 and m2 (m2>m1) are connected by a line in extensible string passing over a smooth fixed pulley. Initially, both masses hang vertically with mass m2 at a height x above the floor. If the system is released from rest, with what speed will mass m2 hit the floor and the mass will rise a further distance (m2-m1) x) /m1+m2 after this occurs |
Answer» The height is h = (m2 - m 1 )(m2 + m 1)xExplanation: (m2 + m 1 )a = (m 2−m 1)g → a= (m 2 - m 1 )(m 2 + m 1 ) g V^2 =2ax The speed is v = √(m 2 - m 1 )(m 2+ m 1 )2gx For mass m2 we can apply the conservation of energy PRINCIPLE: m 2gh = 0.5 m 2 v^2 h = (m2 - m 1 )(m2 + m 1)x Thus the height is h = (m2 - m 1 )(m2 + m 1)x Also learn more A boy on a 20 m high cliff drops a stone. One second LATER, he throws down another stone. Both the stones HIT the ground simultaneously. Find the initial velocity of the second stone. ? |
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