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Particles of masses `1kg` and `3kg` are at `2i + 5j + 13k)m` and `(-6i + 4j - 2k)m` then instantaneous position of their centre of mass isA. `1/4(-16i+17j+7k)m`B. `1/4(-8i+17j+7k)m`C. `1/4(-6i+17j+7k)m`D. `1/4(-6i+17j+5k)m` |
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Answer» Correct Answer - A `vec(r)_(cm)=(m_(1)vec(r)_(1)+m_(2)vec(r)_(2))/(m_(1)+m_(2))` |
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