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`Pb(CH_(3)COO)_(2)` gives . . . Colour with `H_(2)S`A. OrangeB. RedC. BlackD. White

Answer» Correct Answer - C
`(CH_(3)COO)_(2),Pb+H_(2)S to 2CH_(3)COOH+underset("black ppt.")(PbS) darr`


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