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' περαHoodle53.A charged oil drop is suspended in uniformfield of 3 x 104 V/m so that it neither fallsnor rises. The charge on the drop will be(take the mass of the charge = 9.9x10-15 kg& g=10 m/s)(D) 328 10-18 C |
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Answer» (c) At equilibrium, electric force on drop balances weight of drop. qE = mg ? q = mg /E q = 9.9 x 10^-15x 10 / 3 x 10^4= 3.3 x 10^-18© |
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