Percentage change in distance is 4. Find % change in Coulomb’s Force

1.	Percentage change in distance is 4. Find % change in Coulomb’s Force.
Answer» Answer: In Coulomb’s Law, F = kq1Q2/d^2 where F is the electric force, k is a constant, q1 and q2 are the two charges and d^2 is the square of the distance between the two charges, let this ORIGINAL value equals to 100%. If d is QUADRUPLED, (4d)^2 becomes 16 d^2. Plugging in this to Coulomb’s law its value related to the electric force is F = (1/16) d^2. The enclosed number (1/16) in PERCENT is 6.25%. The percentage change in coulomb force is therefore 100% - 6.25% or 93.75%.

Percentage change in distance is 4. Find % change in Coulomb’s Force.

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Answer:

In Coulomb’s Law, F = k*q1*Q2/d^2 where F is the electric force, k is a constant, q1 and q2 are the two charges and d^2 is the square of the distance between the two charges, let this ORIGINAL value equals to 100%.

If d is QUADRUPLED, (4d)^2 becomes 16 d^2. Plugging in this to Coulomb’s law its value related to the electric force is F = (1/16) d^2. The enclosed number (1/16) in PERCENT is 6.25%. The percentage change in coulomb force is therefore 100% - 6.25% or 93.75%.

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Percentage change in distance is 4. Find % change in Coulomb’s Force.

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