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person walks along a straight road firom hishouse to a market 2.5kms away with a speed dof 5 km/hr and instantly turns back andreaches his house with a speed of 7.5 kms/hr.The average speed of the person during thetime interval 0 to 50 minutes is (in m/sec)2353)1) 44) |
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Answer» 0 to50 minTime = 50 min=50/60 = 5/6 hNet displacement = 0Total distance = 2.5 + 2.5 = 5 kmAverage velocity = Displacement / Time = 0Average speed = Distance / Time = 5/(5/6) = 6 km/h ans in m/sec |
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