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`pH` of a solution of `10 ml`. `1 N` sodium acetate and `50 ml 2N` acetic acid `(K_(a)=1.8xx10^(-5))` is approximatelyA. `4`B. `5`C. `6`D. `7` |
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Answer» Correct Answer - A `pH=pK_(a)+log``([Sal t])/([Acid])` `pH= -log(1.8xx10^(-5))+log``([10])/([100])` `=-log 1.8+5+log 10^(-1)` `= -0.2553+5-1=3.7447` or `=4` |
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