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Answer» Maximum torque on the dipole = 2 x 10⁻² N mExplanation:Electric Field E = 10⁵ NC⁻¹Magnitude of charge q = 10μC = 10⁻⁵ Cdipole length 2a = 2 cm = 2 x 10⁻² MMAGNITUDE of torque τ = p E sinθMaximum torque τ = p E = q x 2a x E = 10⁻⁵ x 2 x 10⁻² x10⁵ = 2 x 10⁻² N MTHE direction of torque is perpendicular to both vectors p and E Magnitude of torque = |
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