Please answer as fast as possible. Q 25

1.	Please answer as fast as possible. Q 25
Answer» ANSWER: Energy of INCIDENT LIGHT: E = hclamda E = 6.6×10^-343×108200×10^-9 E = 9.9×10^-20J Work Function: W = hclamda×o W = 6.6×10^-343×108250×10^-9 W = 7.92×10^-20J Energy of the EMITTED electrons: K.E = E-W K.E = 9.9×10^-20J - 7.92×10^-20J *K.E = 19.8×10^-20J*

Answer»

ANSWER:

Energy of INCIDENT LIGHT:

E = hclamda

E = 6.6×10^-343×108200×10^-9

E = 9.9×10^-20J

Work Function:

W = hclamda×o

W = 6.6×10^-343×108250×10^-9

W = 7.92×10^-20J

Energy of the EMITTED electrons:

K.E = E-W

K.E = 9.9×10^-20J - 7.92×10^-20J

K.E = 19.8×10^-20J

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Please answer as fast as possible. Q 25

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