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Please give me the solution of this question urgently |
Answer» Answer:Question:Tuning fork A produces 4 beats with tuning fork B of frequency 346 Hz. When tuning fork A is FILED, the NUMBER of beats heard is 6 per SEC. Find original frequency of Tuning fork A. Given:Beat frequency = 4 Hz. Frequency of B = 346 Hz. If Tuning fork A is filed, then beat frequency becomes 6 To find:Frequency of Tuning fork A. Concept:We don't know if frequency of Tuning fork A is greater or lesser than that of Tuning Fork B So, either of the 2 Equations can form : Now , we know that if a tuning fork is filed, then it's frequency increases . This is possible only in Equation (1) So taking Equation (1) in consideration: So final answer is 350 Hz. |
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