Please help in Calculating Acceleration if the car starts from rest an

1.	Please help in Calculating Acceleration if the car starts from rest and gains a Velocity of 5 m/s in 2 s. Don't forget to find Distance Travelled
Answer» <U>Given : Initial velocity (u) = 0 Final velocity (v) = 5m/s Time (t) = 2S To find : Acceleration (a) Distance (s) Solution : ✞According to the first EQUATION of MOTION $\bigstar{\large{\boxed{\bf{\red{v=u+at}}}}} \\ \\ \implies\large\tt 5=0+a\times{2} \\ \\ \\ \implies\large\tt 5=2a \\ \\ \\ \implies\large\tt a=\cancel\dfrac{5}{2} \\ \\ \\ \implies\large\tt a=2.5m/s^2$ Hence, Acceleration of car is 2.5m/s² $\rule{200}3$ ✞Now, according to the second equation of motion $\bigstar{\large{\boxed{\bf{\red{s=ut+\dfrac{1}{2}at^2}}}}} \\ \\ \implies\large\tt s=0\times{2}+\dfrac{1}{2}\times{2.5}\times{(2)^2} \\ \\ \\ \implies\large\tt s=0+\dfrac{1}{2}\times{2.5}\times{4} \\ \\ \\ \implies\large\tt s=2.5\times{2} \\ \\ \\ \implies\large\tt s=5m$ Hence, Distance covered by a car is 5m $\rule{200}3$

Please help in Calculating Acceleration if the car starts from rest and gains a Velocity of 5 m/s in 2 s. Don't forget to find Distance Travelled

Answer»

<U>Given :

Initial velocity (u) = 0
Final velocity (v) = 5m/s
Time (t) = 2S

To find :

Acceleration (a)
Distance (s)

Solution :

✞According to the first EQUATION of MOTION

$\bigstar{\large{\boxed{\bf{\red{v=u+at}}}}} \\ \\ \implies\large\tt 5=0+a\times{2} \\ \\ \\ \implies\large\tt 5=2a \\ \\ \\ \implies\large\tt a=\cancel\dfrac{5}{2} \\ \\ \\ \implies\large\tt a=2.5m/s^2$

Hence,

Acceleration of car is 2.5m/s²

$\rule{200}3$

✞Now, according to the second equation of motion

$\bigstar{\large{\boxed{\bf{\red{s=ut+\dfrac{1}{2}at^2}}}}} \\ \\ \implies\large\tt s=0\times{2}+\dfrac{1}{2}\times{2.5}\times{(2)^2} \\ \\ \\ \implies\large\tt s=0+\dfrac{1}{2}\times{2.5}\times{4} \\ \\ \\ \implies\large\tt s=2.5\times{2} \\ \\ \\ \implies\large\tt s=5m$

Hence,

Distance covered by a car is 5m

$\rule{200}3$