Saved Bookmarks
| 1. |
Please help, show your working. |
|
Answer» s m is HUNG to the initial spring of unstreached LENGTH L and Force Constant k.Also,LET the the extension in the spring be = x.At Balanced Condition :-NOTE : NEGATIVE sign is ignored because it only represents the direction of the ForceWe Know That ,Extension in the spring is directly proportional to length of unstretched spring,Hence,Putting Value of x in (1)When The spring is cut into two parts of unstreached length and Force Constant We Have,Obviously,Putting (4) in (3) We Get :From (2) :- Using (4) :-Also,Using (5) :- |
|